Star American guard Dwyane Wade officially became a player “Cleveland Cavaliers”.
To be in Cleveland, Wade a few days before moving to Ohio has agreed with the Chicago early termination of the contract – the former leader of “Miami” declined to eight million dollars from 23,8 owed to him by the last year of the agreement with the bulls.
Wade signed with the “Cleveland” one-year contract for $ 2.3 million. To debut in the new team a 35-year-old defender will be able to the fifth of October, when the Cavaliers will hold a preseason meeting with Atlanta.
“I always dreamed of playing for the “Chicago” and happy that he realized his dream last season. Now the team went in a different direction, it made me reconsider where I should be at this stage of his career.
“Cleveland” today is the best team to continue his career and fight at the highest level. They believe in my talent and my ability to help a contender for the championship both as a player and as a leader,” Wade wrote on his page on “Twitter”.
Dwyane Wade is a three-time NBA champion (2006, 2012, 2013), 12-multiple participant Matches all-star and Olympic champion in 2008.
NBA star rookie “Cleveland” played 915 games, averaging per game at 23.3 points, 4.8 rebounds and 5.7 assists.
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